問題詳情
70 如附圖，受測者手肘屈曲 60 度，手中握一個重量為 3 磅的鍋子，假設由手肘軸心至鍋子握把之距離為 14 吋，則作用在手肘之力矩（torque）約為多少？ 
（sin30° =0.5，cos30° =0.866）
(A) 21.2 吋‧磅
(B) 28.0 吋‧磅
(C) 36.4 吋‧磅
(D) 42.4 吋‧磅
（sin30° =0.5，cos30° =0.866）(A) 21.2 吋‧磅
(B) 28.0 吋‧磅
(C) 36.4 吋‧磅
(D) 42.4 吋‧磅
參考答案
答案：C
難度：困難0.362319
統計：A(19),B(13),C(25),D(8),E(0)
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