問題詳情
9如圖所示，磁場強度為 0.T，若導線 AD 以 m∕s 的速度向右，圖中 
＝m，R＝10Ω，若導線等速運動，線圈內應電流為
(A)4√3/
(B)4/
(C)2√3/
(D)4/5√(Ｅ)2/A。
＝m，R＝10Ω，若導線等速運動，線圈內應電流為 (A)4√3/
(B)4/
(C)2√3/
(D)4/5√(Ｅ)2/A。
參考答案
答案：C
難度：非常困難0
統計：A(0),B(0),C(0),D(0),E(0)
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