問題詳情
22）有以下程序main(){int k=5,n=0;do{switch(k){case 1: case 3:n+=1;k--;break;default:n=0;k--;case 2: case 4:n+=2;k--;break;}printf("%d",n);}while(k>0 && n<5);}程序运行后的输出结果是
(A)235
(B)0235
(C)02356
(D)2356
(A)235
(B)0235
(C)02356
(D)2356
參考答案
答案：A
難度：適中0.5
統計：A(0),B(0),C(0),D(0),E(0)
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