問題詳情

69 As a convenience feature, your web pages include an Ajax request every five minutes to aspecial servlet that monitors the age of the user's session. The client-side JavaScript that handles theAjax callback displays a message on the screen as the session ages. The Ajax call does NOT pass anycookies, but it passes the session ID in a request parameter called sessionI
(D) In addition, assume thatyour webapp keeps a hasmap of session objects by the I
(D) Here is a partial implementation of thisservlet:10. public class SessionAgeServlet extends HttpServlet {11. public void service(HttpServletRequest request, HttpServletResponse) throws IOException {12. String sessionID = request.getParameter("sessionID");13. HttpSession session = getSession(sessionID);14. long age = // your code here15. response.getWriter().print(age);16. }... // more code here47. }Which code snippet on line 14, will determine the age of the session?
(A) session.getMaxInactiveInterval();
(B) session.getLastAccessed().getTime() - session.getCreationTime().getTime();
(C) session.getLastAccessedTime().getTime() - session.getCreationTime().getTime();
(D) session.getLastAccessed() - session.getCreationTime();
(E) session.getMaxInactiveInterval() - session.getCreationTime();F. session.getLastAccessedTime() - session.getCreationTime();

編輯私有筆記及自訂標籤OCE-Java EE 6 Web Component Developer Certified Expert Exam:1z0-899(51-100)#84004
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