問題詳情

Passage TwoMore and more, the operations of our businesses, governments, and financialinstitutions are controlled by information that exists only inside computer memories. Anyoneclever enough to modify this information for his own purposes can reap big reward. Evenworse, a number of people who have done this and been caught at it have managed to getaway without punishment.It’s easy for computer crimes to go undetected if no one checks up on what thecomputer is doing. But even if the crime is detected, the criminal may walk away not onlyunpunished but with a glowing recommendation from his former employers.Of course, we have no statistics on crimes that go undetected. But it’s disturbing to notehow many of the crimes we do know about were detected by accident, not by systematicinspections or other security procedures. The computer criminals who have been caught mayhave been the victims of uncommonly bad luck.Unlike other lawbreakers, who must leave the country, commit suicide, or go to jail,computer criminals sometimes escape punishment, demanding not only that they not becharged but that they be given good recommendations and perhaps other benefits. All toooften, their demands have been met.Why? Because company executives are afraid of the bad publicity that would result ifthe public found out that their computer had been misused. They hesitate at the thought of acriminal boasting in open court of how he juggled (篡改) the most confidential (保密)records right under the noses of the company’s executives, accountants, and security staff.And so another computer criminal departs with just the recommendations he needs tocontinue his crimes elsewhere.
46. It can be concluded from the passage that ______.
(A)it is still impossible to detect computer crimes today
(B)people commit computer crimes at the request of their company
(C)computer criminals escape punishment because they can’t be detected
(D)computer crimes are the most serious problem in the operation of financial institutions

參考答案

答案：D
難度：適中0.5
統計：A(0),B(0),C(0),D(0),E(0)

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