問題詳情
With the rising number of vehicles and the limited parking spaces, city traffic has become a serious problem.More cars are produced every year and the streets are getting more and more crowded. So during rush hours, when people are going to or from their work, traffic is brought to a standstill. It has been suggested that people should share their cars and give each other lifts. So each car would carry four or five people instead of only one. This carpool project is a good idea; however, so far nobody has been able to think of a way to make people do so.Roadside parking can be one of the solutions to traffic problems. When you park at a meter along the road, you must put a coin in the slot. This pays for a certain amount of time. The meter records this and it shows the time that you have paid for is finished. If the car is still there then, you have to pay a fine. Traffic wardens look after the meters. If a meter shows “TIME EXPIRED”, the motorist who has left his car there will be fined. Of course, the traffic warden cannot wait for the owner of the car there to be fined. It is impossible to wait for the owner of the car to return so the traffic warden carries a pile of paper, and on one of these he writes down all the details, such as the number of the car, where it is parked, how much the driver must pay and where he must send the money. He leaves this form on the car where the driver will be able to see it easily. When the driver comes back, he gets an unpleasant surprise. The ticket can be a reminder. Next time, he’d better watch out for the expiry time.
68. The suggestion that people should share their car has not been accepted because ______.
(A) it is not useful enough
(B) drivers don’t like it
(C) it is difficult to carry out
(D) most people are against it
68. The suggestion that people should share their car has not been accepted because ______.
(A) it is not useful enough
(B) drivers don’t like it
(C) it is difficult to carry out
(D) most people are against it
參考答案
答案:[無官方正解]
難度:適中0.5
統計:A(0),B(0),C(0),D(0),E(0)
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